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Artifact 7bb0e4dbe808f1b79803b8dad337037b3e3f9411:


dnl  AMD K7 mpn_copyi -- copy limb vector, incrementing.

dnl  Copyright 1999, 2000, 2002 Free Software Foundation, Inc.
dnl 
dnl  This file is part of the GNU MP Library.
dnl 
dnl  The GNU MP Library is free software; you can redistribute it and/or
dnl  modify it under the terms of the GNU Lesser General Public License as
dnl  published by the Free Software Foundation; either version 2.1 of the
dnl  License, or (at your option) any later version.
dnl 
dnl  The GNU MP Library is distributed in the hope that it will be useful,
dnl  but WITHOUT ANY WARRANTY; without even the implied warranty of
dnl  MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
dnl  Lesser General Public License for more details.
dnl 
dnl  You should have received a copy of the GNU Lesser General Public
dnl  License along with the GNU MP Library; see the file COPYING.LIB.  If
dnl  not, write to the Free Software Foundation, Inc., 59 Temple Place -
dnl  Suite 330, Boston, MA 02111-1307, USA.

include(`../config.m4')


C    alignment dst/src, A=0mod8 N=4mod8
C       A/A   A/N   N/A   N/N
C K7    0.75  1.0   1.0   0.75


C void mpn_copyi (mp_ptr dst, mp_srcptr src, mp_size_t size);
C
C Copy src,size to dst,size.
C
C This code at 0.75 or 1.0 c/l is always faster than a plain rep movsl at
C 1.33 c/l.
C
C The K7 can do two loads, or two stores, or a load and a store, in one
C cycle, so if those are 64-bit operations then 0.5 c/l should be possible,
C however nothing under 0.7 c/l is known.
C
C If both source and destination are unaligned then one limb is processed at
C the start to make them aligned and so get 0.75 c/l, whereas if they'd been
C used unaligned it would be 1.5 c/l.

defframe(PARAM_SIZE,12)
defframe(PARAM_SRC, 8)
defframe(PARAM_DST, 4)

dnl  parameter space reused
define(SAVE_EBX,`PARAM_SIZE')

dnl  minimum 5 since the unrolled code can't handle less than 5
deflit(UNROLL_THRESHOLD, 5)

	TEXT
	ALIGN(32)
PROLOGUE(mpn_copyi)
deflit(`FRAME',0)

	movl	PARAM_SIZE, %ecx
	movl	%ebx, SAVE_EBX

	movl	PARAM_SRC, %eax
	movl	PARAM_DST, %edx

	cmpl	$UNROLL_THRESHOLD, %ecx
	jae	L(unroll)

	orl	%ecx, %ecx
	jz	L(simple_done)

L(simple):
	C eax	src, incrementing
	C ebx	scratch
	C ecx	counter
	C edx	dst, incrementing
	C
	C this loop is 2 cycles/limb

	movl	(%eax), %ebx
	movl	%ebx, (%edx)
	decl	%ecx
	leal	4(%eax), %eax
	leal	4(%edx), %edx
	jnz	L(simple)

L(simple_done):
	movl	SAVE_EBX, %ebx
	ret


L(unroll):
	movl	%eax, %ebx
	leal	-12(%eax,%ecx,4), %eax	C src end - 12
	subl	$3, %ecx		C size-3

	andl	%edx, %ebx
	leal	(%edx,%ecx,4), %edx	C dst end - 12
	negl	%ecx

	testl	$4, %ebx   C testl to pad code closer to 16 bytes for L(top)
	jz	L(aligned)

	C both src and dst unaligned, process one limb to align them
	movl	(%eax,%ecx,4), %ebx
	movl	%ebx, (%edx,%ecx,4)
	incl	%ecx
L(aligned):


	ALIGN(16)
L(top):
	C eax	src end - 12
	C ebx
	C ecx	counter, negative, limbs
	C edx	dst end - 12

	movq	(%eax,%ecx,4), %mm0
	movq	8(%eax,%ecx,4), %mm1
	addl	$4, %ecx
	movq	%mm0, -16(%edx,%ecx,4)
	movq	%mm1, -16+8(%edx,%ecx,4)
	ja	L(top)		C jump no carry and not zero


	C now %ecx is 0 to 3 representing respectively 3 to 0 limbs remaining

	testb	$2, %cl
	jnz	L(finish_not_two)

	movq	(%eax,%ecx,4), %mm0
	movq	%mm0, (%edx,%ecx,4)
L(finish_not_two):

	testb	$1, %cl
	jnz	L(done)

	movl	8(%eax), %ebx
	movl	%ebx, 8(%edx)

L(done):
	movl	SAVE_EBX, %ebx
	emms
	ret

EPILOGUE()